A) 4 : 3
B) 3 : 4
C) 2 : 3
D) 3 : 2
Correct Answer: A
Solution :
\[{{C}_{AB}}=3+\frac{3}{3}=4,\mu F\] \[{{C}_{AC}}=\frac{3}{2}+\frac{3}{2}=3\mu F\] \\[{{C}_{AB}}:{{C}_{AC}}=4:\,3\]You need to login to perform this action.
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