A) \[2\mu F\]
B) \[4\mu F\]
C) \[18\mu F\]
D) \[10\mu F\]
Correct Answer: C
Solution :
By using, common potential \[V=\frac{{{C}_{1}}{{V}_{1}}+{{C}_{2}}{{V}_{2}}}{{{C}_{1}}+{{C}_{2}}}\] Þ \[20=\frac{2\times 200+{{C}_{2}}\times 0}{2+{{C}_{2}}}\] Þ \[{{C}_{2}}=18\mu F\]You need to login to perform this action.
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