A) \[\frac{6}{14}\] and \[50\ volt\]
B) \[\frac{14}{6}\] and \[30\ volt\]
C) \[\frac{6}{14}\] and \[30\ volt\]
D) \[\frac{14}{6}\] and 0\[volt\]
Correct Answer: C
Solution :
Let \[{{q}_{1}},\,{{q}_{2}}\] be the charges on two condensers \ \[V=\frac{{{q}_{1}}}{6}=\frac{{{q}_{2}}}{14}\] Þ \[\frac{{{q}_{1}}}{{{q}_{2}}}=\frac{6}{14}=\frac{3}{7}\] Also \[{{q}_{1}}+{{q}_{2}}=600\]Þ \[{{q}_{1}}+\frac{14}{6}{{q}_{1}}=600\]Þ \[{{q}_{1}}=\frac{600}{20}\times 6\] \ \[V=\frac{{{q}_{1}}}{6}=\frac{600}{20}=30\,volt\]You need to login to perform this action.
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