question_answer

The equivalent capacitance between A and B is                                                 [RPMT 1999]

A)            2\[\mu \,F\]                         

B)            3\[\mu \,F\]

C)            5\[\mu \,F\]                         

D)            0.5\[\mu \,F\]

Correct Answer: D

Solution :

                   \[\frac{1}{C}=\frac{1}{2}+\frac{1}{1}+\frac{1}{2}=\frac{1+2+1}{2}=\frac{4}{2}=2\]Þ \[{{C}_{AB}}=0.5\,\mu F\]