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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Grouping of Capacitors

  • question_answer
    A potential difference of 300 volts is applied to a combination of 2.0mF and 8.0mF capacitors connected in series. The charge on the 2.0mF capacitor is                                                                [MP PMT 2000]

    A)            \[2.4\times {{10}^{-4}}\]C

    B)                                      \[4.8\times {{10}^{-4}}\]C

    C)            \[7.2\times {{10}^{-4}}\]C      

    D)            \[9.6\times {{10}^{-4}}\]C

    Correct Answer: B

    Solution :

               In series combination charge Q is same.  So charge on 2mF capacitor is                    \[Q={{C}_{eq}}V=\left( \frac{2\times 8}{2+8} \right)\times 300\times {{10}^{-6}}\]\[=4.8\times {{10}^{-4}}C\]


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