JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Grouping of Capacitors

  • question_answer
    Two capacitors A and B are connected in series with a battery as shown in the figure. When the switch S is closed and the two capacitors get charged fully, then                                                                                            [MP PET 2000]

    A)            The potential difference across the plates of A is 4V and across the plates of B is 6V

    B)            The potential difference across the plates of A is 6V and across the plates of B is 4V

    C)            The ratio of electrical energies stored in A and B is 2 : 3

    D)            The ratio of charges on A and B is 3 : 2

    Correct Answer: B

    Solution :

                       In series combination of capacitors, voltage distributes on them, in the reverse ratio of their capacitance i.e. \[\frac{{{V}_{A}}}{{{V}_{B}}}=\frac{3}{2}\]                            ......(i) Also \[{{V}_{A}}+{{V}_{B}}=\text{ 1}0\]            .......(ii)                    On solving (i) and (ii) \[{{V}_{A}}=\text{ 6}V,{{V}_{B}}=\text{ 4}V\]


You need to login to perform this action.
You will be redirected in 3 sec spinner