A) \[9\times {{10}^{-12}}\,F\]
B) \[6\times {{10}^{-12}}\,F\]
C) \[3\times {{10}^{-12}}\,F\]
D) \[2\times {{10}^{-12}}\,F\]
Correct Answer: D
Solution :
\[{C}'=C/n=\frac{6\times {{10}^{-12}}}{3}=2\times {{10}^{-12}}F\]
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