A) 25 J
B) 200 J
C) 125 J
D) 150 J
Correct Answer: D
Solution :
\[\Delta U=\frac{{{C}_{1}}{{C}_{2}}}{2({{C}_{1}}+{{C}_{2}})}{{({{V}_{1}}-{{V}_{2}})}^{2}}\]\[=\frac{20\times 30}{2(20+30)}{{(5-0)}^{2}}=150J\]
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