JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Grouping of Resistances

  • question_answer
    There are \[n\] similar conductors each of resistance \[R\]. The resultant resistance comes out to be \[x\] when connected in parallel. If they are connected in series, the resistance comes out to be                                     [DPMT 2004]

    A)                    \[x/{{n}^{2}}\]

    B)                                      \[{{n}^{2}}x\]

    C)                    \[x/n\]                            

    D)            \[nx\]

    Correct Answer: B

    Solution :

                 In parallel, \[x=\frac{R}{n}\]  \[R=nx\] In series, R + R + R ....n times \[=nR=n\left( nx \right)\text{ }={{n}^{2}}x\]


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