A) \[\frac{14}{3}\,\,\Omega \]
B) \[\frac{3}{14}\,\,\Omega \]
C) \[\frac{9}{14}\,\,\Omega \]
D) \[\frac{14}{9}\,\,\Omega \]
Correct Answer: A
Solution :
The given circuit is a balanced Wheatstone bridge, hence it can be redrawn as follows \[\Rightarrow \,\,\,\,\,\,{{R}_{eq}}=\frac{7\times 14}{(7+14)}=\frac{14}{3}\Omega \].You need to login to perform this action.
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