A) 1 V
B) 2 V
C) 3 V
D) 0.5 V
Correct Answer: A
Solution :
The circuit can be drawn as follows Equivalent resistance \[R=\frac{3\times (3+3)}{3+(3+3)}=2\Omega \] Current \[i=\frac{2}{2}=1A.\] So,\[{{i}_{1}}=1\times \left( \frac{3}{3+6} \right)=\frac{1}{3}A\]. Potential difference between A and B =\[\frac{1}{3}\times 3=1volt.\]You need to login to perform this action.
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