A) 4.5 V
B) 1.2 V
C) 2.4 V
D) 2.88 V
Correct Answer: D
Solution :
Equivalent resistance between P and Q \[\frac{1}{{{R}_{PQ}}}=\frac{1}{(6+2)}+\frac{1}{3}+\frac{1}{(4+12)}\] Þ \[{{R}_{PQ}}=\frac{48}{25}\Omega \] Current between P and Q; i = 1.5A So, potential difference between P and Q \[{{V}_{PQ}}=1.5\times \frac{48}{25}=2.88V\].
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