A) 10 W should be connected in parallel with A
B) 10 W should be connected in series with A
C) 5 W should be connected in series with B
D) 5 W should be connected in parallel with B
Correct Answer: A
Solution :
For a balance Wheatstone bridge. \[\frac{A}{B}=\frac{D}{C}\Rightarrow \frac{10}{5}\ne \frac{4}{4}\text{ (Unbalanced)}\] \[\frac{A'}{B}=\frac{D}{C}\Rightarrow \frac{A'}{5}=\frac{4}{4}\]\[\Rightarrow \] \[A'=5\Omega \] \[A'(5\Omega )\] is obtained by connecting a \[10\,\Omega \] resistance in parallel with A.
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