A) 60
B) 40
C) 20
D) 10
Correct Answer: C
Solution :
For first balancing condition \[\frac{10+{{R}_{1}}}{{{R}_{2}}}=\frac{50}{50}\] Þ \[{{R}_{2}}=10+{{R}_{1}}\]. For second balancing condition \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{40}{60}\]Þ \[\frac{{{R}_{1}}}{10+{{R}_{1}}}=\frac{2}{3}\] Þ \[{{R}_{1}}=20\,\Omega \]
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