A) 4 W, 8 V
B) 8 W, 4 V
C) 2 W, 2 V
D) 16 W, 8 V
Correct Answer: A
Solution :
The equivalent resistance between C and D is \[\frac{1}{R'}=\frac{1}{6}+\frac{1}{6}+\frac{1}{3}=\frac{2}{3}\] or \[R'=\frac{3}{2}=1.5\,\Omega \] Now the equivalent resistance between A and B as \[R'=1.5\,\Omega \] and \[2.5\,\Omega \] are connected in series, so \[R''=1.5+2.5=4\,\Omega \] Now by ohm's law, potential difference between A and B is given by \[{{V}_{A}}-{{V}_{B}}=iR=2\times 4.0\]\[=8\,\,volt\]
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