JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Grouping of Resistances

  • question_answer
    In the circuit given E = 6.0 V, R1 = 100 ohms, R2 = R3 = 50 ohms, R4 = 75 ohms. The equivalent resistance of the circuit, in ohms, is                                                                          [KCET 2005]

    A)         11.875

    B)         26.31

    C)         118.75

    D)         None of these

    Correct Answer: C

    Solution :

                                             In given circuit three resistance \[{{R}_{2}},{{R}_{4}}\] and \[{{R}_{3}}\] are parallel.                    \[\frac{1}{R}=\frac{1}{{{R}_{2}}}+\frac{1}{{{R}_{4}}}+\frac{1}{{{R}_{3}}}\]                    \[=\frac{1}{50}+\frac{1}{50}+\frac{1}{75}\]                    \[=\frac{75+75+50}{50\times 75}\]                    \[R=\frac{50\times 75}{75+75+50}=\frac{50\times 75}{200}=\frac{75}{4}\Omega =18.75\Omega \]                    This resistance is in series with \[{{R}_{1}}\]                                                    \ \[{{R}_{\text{resultant}}}={{R}_{1}}+R=100+18.75=118.75\Omega \]


You need to login to perform this action.
You will be redirected in 3 sec spinner