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JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Grouping of Resistances

  • question_answer
    Two resistances are joined in parallel whose resultant is \[\frac{6}{8}\]ohm. One of the resistance wire is broken and the effective resistance becomes \[2\,\Omega \]. Then the resistance in ohm of the wire that got broken was                                                                          [CPMT 1976; DPMT 1982]

    A)                    3/5

    B)                                      2

    C)                    6/5                                    

    D)            3

    Correct Answer: C

    Solution :

                 If resistances are \[{{R}_{1}}\] and \[{{R}_{2}}\] then \[\frac{{{R}_{1}}{{R}_{2}}}{{{R}_{1}}+{{R}_{2}}}=\frac{6}{8}\] ?..(i)                    Suppose \[{{R}_{2}}\] is broken then \[{{R}_{1}}=2\Omega \]  ?..(ii) On solving equations (i) and (ii) we get \[{{R}_{2}}=6/5\,\Omega \]


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