question_answer

Resistors of 1, 2, 3 ohm are connected in the form of a triangle. If a 1.5 volt cell of negligible internal resistance is connected across 3 ohm resistor, the current flowing through this resistance will be                                        [CPMT 1984]

A)                    0.25 amp                        

B)            0.5 amp

C)                    1.0 amp                          

D)            1.5 amp

Correct Answer: B

Solution :

             \[{{i}_{1}}+{{i}_{2}}=\frac{1.5}{3/2}=1\,amp\] \[\frac{{{i}_{1}}}{{{i}_{2}}}=\frac{3}{3}\]  Þ \[{{i}_{1}}={{i}_{2}}\]  \ \[{{i}_{2}}=0.5A={{i}_{1}}\]