JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Grouping of Resistances

  • question_answer
    Resistances of 6 ohm each are connected in the manner shown in adjoining figure. With the current 0.5 ampere as shown in figure, the potential difference \[{{V}_{P}}-{{V}_{Q}}\] is [CPMT 1989]

    A)                    3.6 V

    B)                                      6.0 V

    C)                    3.0 V

    D)            7.2 V

    Correct Answer: C

    Solution :

                 \[{{V}_{p}}-{{V}_{q}}=\left( \frac{6}{3}+\frac{12\times 6}{12+6} \right)\,(0.5)=(2+4)\,(0.5)=3V\]


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