A) 2 amp and 4 amp
B) 1 amp and 2 amp
C) 1 amp and 1 amp
D) 2 amp and 2 amp
Correct Answer: D
Solution :
Equivalent resistance \[=\frac{4\times 4}{4+4}+\frac{6\times 6}{6+6}=5ohm\] So the current in the circuit \[=\frac{20}{5}=4\]ampere Hence the current flowing through each resistance = 2 ampere.
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