JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Grouping of Resistances

  • question_answer
    A wire of resistance R is divided in 10 equal parts. These parts are connected in parallel, the equivalent resistance of such connection will be                                        [CPMT 1973, 91]

    A)                    0.01 R

    B)                    0.1 R

    C)                    10 R                                  

    D)            100 R

    Correct Answer: A

    Solution :

                 Each part will have a resistance \[r=R/10\]                   Let equivalent resistance be \[{{r}_{R,}}\]then                                 \[\frac{1}{{{r}_{R}}}=\frac{1}{r}+\frac{1}{r}+\frac{1}{r}...........10\ \text{times}\]                    \[\therefore \frac{1}{{{r}_{R}}}=\frac{10}{r}=\frac{10}{R/10}=\frac{100}{R}\Rightarrow {{r}_{R}}=\frac{R}{100}=0.01R\]


You need to login to perform this action.
You will be redirected in 3 sec spinner