A) Zero
B) \[-\,8\,V\]
C) \[-\,4/3\,V\]
D) 4/3 V
Correct Answer: C
Solution :
The current in the circuit \[=\frac{8}{5+1}=\frac{4}{3}\] Now \[{{V}_{C}}-{{V}_{E}}=\frac{4}{3}\times 1\] Þ \[{{V}_{E}}=-\frac{4}{3}V\]
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