A) 9 ohm
B) 3 ohm
C) 1 ohm
D) \[\frac{1}{3}ohm\]
Correct Answer: C
Solution :
\[\frac{1}{R}=\frac{1}{1}+\frac{1}{1}+\frac{1}{1}=\frac{3}{1}\] Þ \[R=\frac{1}{3}\,ohm\] Now such three resistance are joined in series, hence total \[R=\frac{1}{3}+\frac{1}{3}+\frac{1}{3}=1ohm\]
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