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JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Grouping of Resistances

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    The current in the adjoining circuit will be   [IIT 1983; CPMT 1991, 92; MH CET 2002; Pb. PMT 2001; Kerala PMT 2004]

    A)                    \[\frac{1}{45}ampere\]

    B)                    \[\frac{1}{15}ampere\]

    C)                    \[\frac{1}{10}ampere\]

    D)                    \[\frac{1}{5}ampere\]

    Correct Answer: C

    Solution :

       \[{{R}_{\text{equivalent}}}=\frac{(30+30)30}{(30+30)+30}=\frac{60\times 30}{90}=20\Omega \]                    \[\therefore i=\frac{V}{R}=\frac{2}{20}=\frac{1}{10}\,ampere\]


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