A) R
B) \[\frac{R}{4}\]
C) \[\frac{R}{5}\]
D) \[\frac{R}{25}\]
Correct Answer: D
Solution :
\[R\propto l\] Hence every new piece will have a resistance \[\frac{R}{10}.\] If two pieces are connected in series, then their resistance \[=\frac{2R}{10}=\frac{R}{5}\] If 5 such combinations are joined in parallel, then net resistance \[=\frac{R}{5\times 5}=\frac{R}{25}\]
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