A) 6 V
B) 4 V
C) 2 V
D) \[-2\,V\]
Correct Answer: D
Solution :
Equivalent external resistance of the given circuit \[{{R}_{eq}}=4\,\Omega \] Current given by the cell \[i=\frac{E}{{{R}_{eq}}+r}=\frac{10}{(4+1)}=2\,A\] Hence, \[({{V}_{A}}-{{V}_{B}})=\frac{i}{2}\times ({{R}_{2}}-{{R}_{1}})=\frac{2}{2}(2-4)=-2\,V.\]
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