JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Grouping of Resistances

  • question_answer
    A wire of resistance R is cut into ?n? equal parts. These parts are then connected in parallel. The equivalent  resistance of the combination will be            [MP PMT/PET 1998; BHU 2005]

    A)                    nR

    B)                                      \[\frac{R}{n}\]

    C)                    \[\frac{n}{R}\]             

    D)            \[\frac{R}{{{n}^{2}}}\]

    Correct Answer: D

    Solution :

                 Resistance of each part will be \[\frac{R}{n}\]; such n parts are joined in parallel so \[{{R}_{eq}}=\frac{R}{{{n}^{2}}}\].


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