JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Grouping of Resistances

  • question_answer
    In the figure, current through the \[3\,\Omega \] resistor is 0.8 ampere, then potential drop through \[4\,\Omega \] resistor is                                           [CBSE PMT 1993; AFMC 1999; MP PMT 2004]

    A)                    9.6 V

    B)                    2.6 V

    C)                    4.8 V

    D)                    1.2 V

    Correct Answer: C

    Solution :

                 Current through 6W resistance in parallel with 3W resistance = 0.4 A So total current = 0.8 + 0.4 = 1.2 A Potential drop across \[4\Omega =1.2\times 4=4.8\,V\]


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