A) \[\frac{5}{3}\Omega \]
B) \[\frac{3}{2}\Omega \]
C) \[1\,\Omega \]
D) \[\frac{2}{3}\Omega \]
Correct Answer: C
Solution :
Resistance of 1 ohm group \[=\frac{R}{n}=\frac{1}{3}\Omega \] This is in series with \[\frac{2}{3}\Omega \]resistor. \[\therefore \]Total resistance \[=\frac{2}{3}+\frac{1}{3}=\frac{3}{3}\Omega =1\Omega \]
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