A) \[40\,\Omega \]
B) \[\frac{40}{3}\Omega \]
C) \[\frac{5}{2}\Omega \]
D) \[100\,\Omega \]
Correct Answer: A
Solution :
For same material and same length \[\frac{{{R}_{2}}}{{{R}_{1}}}=\frac{{{A}_{1}}}{{{A}_{2}}}=\frac{3}{2}\] Þ \[{{R}_{2}}=3{{R}_{1}}\] Resistance of thick wire \[{{R}_{1}}=10\Omega \] \ Resistance of thin wire \[{{R}_{2}}=30\Omega \] Total resistance in series = 10 + 30 = 40 WYou need to login to perform this action.
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