A) \[\frac{1}{8}A\]
B) \[\frac{2}{9}A\]
C) \[\frac{2}{3}A\]
D) \[1A\]
Correct Answer: D
Solution :
Resistance across the battery is \[\frac{1}{{{R}_{p}}}=\frac{1}{3}+\frac{1}{6}=\frac{2+1}{6}=\frac{3}{6}\] Þ \[{{R}_{p}}=2\Omega \]Þ \[I=\frac{2}{2}=1\,A\]
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