A) 8 W
B) 6 W
C) 4 W
D) 2 W
Correct Answer: B
Solution :
\[{{R}_{AB}}={{R}_{1}}+\frac{{{R}_{2}}{{R}_{3}}}{{{R}_{2}}+{{R}_{3}}}+{{R}_{4}}\]= \[2+\frac{4\times 4}{4+4}+2=6\Omega \].
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