JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Grouping of Resistances

  • question_answer
    The potential drop across the 3W resistor is      [CPMT 2000]

    A)         1 V

    B)         1.5 V

    C)         2 V

    D)         3 V

    Correct Answer: A

    Solution :

                                             Equivalent resistance \[R=4+\frac{3\times 6}{3+6}=6\Omega \] and main current \[i=\frac{E}{R}=\frac{3}{6}=0.5A\] Now potential difference across the combination of 3W and 6W, \[V=0.5\times \left( \frac{3\times 6}{3+6} \right)=1Volt\]                                                    The same potential difference, also develops across 3W resistance.


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