JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Grouping of Resistances

  • question_answer
    If each resistance in the figure is of 9 W then reading of ammeter is                                         [RPMT 2000]

    A)         5 A                                    

    B)         8 A

    C)         2 A                                    

    D)         9 A

    Correct Answer: A

    Solution :

                                             Equivalent resistance \[R=\frac{9}{9}=1\Omega \] Current \[i=\frac{9}{1}=9A\]         Current passes through the ammeter = 5A.


You need to login to perform this action.
You will be redirected in 3 sec spinner