Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर
JEE Main & Advanced
Physics
Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर
Question Bank
Grouping of Resistances
question_answer
A uniform wire of resistance 9 W is cut into 3 equal parts. They are connected in the form of equilateral triangle ABC. A cell of e.m.f. 2 V and negligible internal resistance is connected across B and C. Potential difference across AB is [Kerala (Engg.) 2001]
A) 1 V
B) 2 V
C) 3 V
D) 0.5 V
Correct Answer:
A
Solution :
The circuit can be drawn as follows Equivalent resistance \[R=\frac{3\times (3+3)}{3+(3+3)}=2\Omega \] Current \[i=\frac{2}{2}=1A.\] So,\[{{i}_{1}}=1\times \left( \frac{3}{3+6} \right)=\frac{1}{3}A\]. Potential difference between A and B =\[\frac{1}{3}\times 3=1volt.\]