JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Grouping of Resistances

  • question_answer
    The reading of the ammeter as per figure shown is

    A)                    \[\frac{1}{8}A\]

    B)                    \[\frac{3}{4}A\]

    C)                    \[\frac{1}{2}A\]

    D)                    2 A

    Correct Answer: B

    Solution :

                 Resistance across XY \[=\frac{2}{3}\Omega \] Total resistance \[=2+\frac{2}{3}=\frac{8}{3}\Omega \] Current through ammeter \[=\frac{2}{8/3}=\frac{6}{8}=\frac{3}{4}A\] 


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