A) 9.6 V
B) 6.6 V
C) 4.8 V
D) 3.2 V
Correct Answer: D
Solution :
Potential difference across PQ i.e. p.d. across the resistance of 20W, which is V = i × 20 and \[i=\frac{48}{(100+100+80+20)}=0.16A\] \ \[V=0.16\times 20=3.2V\].
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