A) \[{{\rho }_{1}}+{{\rho }_{2}}\]
B) \[\frac{{{\rho }_{1}}+{{\rho }_{2}}}{2}\]
C) \[\sqrt{{{\rho }_{1}}{{\rho }_{2}}}\]
D) \[2({{\rho }_{1}}+{{\rho }_{2}})\]
Correct Answer: B
Solution :
\[{{R}_{eq}}={{R}_{1}}+{{R}_{2}}\]Þ\[\frac{{{\rho }_{eff.2l}}}{A}=\frac{{{\rho }_{1}}l}{A}+\frac{{{\rho }_{2}}l}{A}\]\[\Rightarrow \,{{\rho }_{eff.}}=\frac{{{\rho }_{1}}+{{\rho }_{2}}}{2}\].
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