A) \[\frac{1}{28}\]
B) \[\frac{1}{39}\]
C) \[\frac{1}{6}\]
D) \[\frac{1}{17}\]
Correct Answer: C
Solution :
of H.P. \[=\frac{1}{61}\,\Rightarrow {{T}_{6}}\] of A.P. = 61 and of H.P. \[=\frac{1}{105}\Rightarrow \,{{T}_{10}}\] of A.P. = 105, so \[a+5d=61\] .......(i) and \[a+9d=105\] ?..(ii) From (i) and (ii),\[a=6\] Therefore first term of H.P.\[=\frac{1}{a}=\frac{1}{6}\].You need to login to perform this action.
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