A) \[\frac{{{T}_{C}}-0}{100}=\frac{{{T}_{F}}-32}{180}\]
B) \[\frac{{{T}_{F}}-32}{180}=\frac{{{T}_{K}}+273.15}{100}\]
C) \[\frac{{{T}_{F}}-32}{180}=\frac{{{T}_{K}}-273.15}{180}\]
D) \[\frac{{{T}_{C}}-0}{180}=\frac{{{T}_{F}}-32}{100}\]
Correct Answer: A
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