JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Heat of reaction

  • question_answer
    Calculate the standard heat of formation of carbon disulphide \[(l)\], given that the standard heat of combustion of carbon \[(s)\], sulphur \[(s)\] and carbon disulphide \[(l)\] are \[-393.3,\,-293.72\] and \[-1108.76\,kJ\,mo{{l}^{-1}}\] respectively [Roorkee 1989; BHU 1997]

    A)                 \[-128.02\,kJ\,mo{{l}^{-1}}\]      

    B)                 \[+12.802\,kJ\,mo{{l}^{-1}}\]

    C)                 \[+128.02\,kJ\,mo{{l}^{-1}}\]     

    D)                 \[-12.802\,kJ\,mo{{l}^{-1}}\]

    Correct Answer: C

    Solution :

           \[C+2S\to C{{S}_{2}}\,\,\,\,\Delta H=?\]            \[C+{{O}_{2}}\to C{{O}_{2}}\,\,\,\,\Delta H=-393.3\,\,kJ\]  ?.(i)            \[S+{{O}_{2}}\to S{{O}_{2}}\,\,\,\,\Delta H=-293.72\,\,kJ\]                ?..(ii)            \[C{{S}_{2}}+3{{O}_{2}}\to C{{O}_{2}}+2S{{O}_{2}}\,\,\,\,\Delta H=-1108.76\,kJ\]   ?..(iii)                                 eq. (ii) × 2 + eq. (i) ? (iv) eq. (iii) ? eq. (iv) and find required result .


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