JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Heat of reaction

  • question_answer
    The combustion enthalpies of carbon, hydrogen and methane are \[-395.5\,kJ\,mo{{l}^{-1}}\], \[-285.8\,kJ\,mo{{l}^{-1}}\] and \[-890.4\,kJ\,mo{{l}^{-1}}\] respectively at \[{{25}^{o}}C\]. The value of standard formation enthalpies of methane at that temperature is                [Pb. PMT 1998]

    A)                 \[890.4\,kJ\,mo{{l}^{-1}}\]          

    B)                 \[-298.8\,kJ\,mo{{l}^{-1}}\]

    C)                 \[-74.7\,kJ\,mo{{l}^{-1}}\]           

    D)                 \[-107.7\,kJ\,mo{{l}^{-1}}\]

    Correct Answer: C

    Solution :

           \[C{{H}_{4}}+2{{O}_{2}}\to C{{O}_{2}}+2{{H}_{2}}O,\,\Delta H=-\,890.4\,kJ\]         ?.(i)            \[C+{{O}_{2}}\to C{{O}_{2}},\,\,\,\,\Delta H=-\,395.5\,kJ\] ?..(ii)            \[C+{{O}_{2}}\to C{{O}_{2}},\,\,\,\,\Delta H=-\,395.5\,kJ\] .?.(ii)                    \[{{H}_{2}}+\frac{1}{2}{{O}_{2}}\to {{H}_{2}}O,\,\,\Delta H=-\,285.8\,kJ\]           ?..(iii)                    from (i), (ii), (iii).                    \[\Delta {{H}_{comb\text{.}}}(C{{H}_{4}})\] \[=\Delta {{H}_{f}}(C{{O}_{2}})+2\Delta {{H}_{f}}({{H}_{2}}O)-\Delta {{H}_{f}}(C{{H}_{4}})-2\Delta {{H}_{f}}({{O}_{2}})\]                    \[=-890.4=-395.5+2\,(-285.5)-\Delta {{H}_{f}}(C{{H}_{4}})-2\times 0\]                                 \[\Delta {{H}_{f}}(C{{H}_{4}})=-76.7\,kJ\,mo{{l}^{-1}}\].


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