A) + 147.2 kJ
B) ? 147.2 kJ
C) ? 294.4 kJ
D) + 294.4 kJ
Correct Answer: C
Solution :
\[S+{{O}_{2}}\to S{{O}_{2}},\,\,\,\,\Delta {{H}_{f}}=-\,4.6\,kJ\] \[\because \] 0.5 gm. of sulphur on burning produce 1gm of \[S{{O}_{2}}\] \[\therefore \] 32 gm of sulphur on burning produce 64 gm.. of \[S{{O}_{2}}\] \[\therefore \Delta H=(\,-\,4.6\,kJ\,)\,\,\times 64=-\,294.4\,kJ\].
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