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JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Heat of reaction

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    The heat evolved in the combustion of benzene is given by the equation \[{{C}_{6}}{{H}_{6}}(l)+7\frac{1}{2}{{O}_{2}}(g)\,\,\to \,\,3{{H}_{2}}O(l)+6C{{O}_{2}}(g)\] \[\Delta H=781.0\,kcal\,\,mo{{l}^{-1}}\] Which of the following quantities of heat energy will be evolved when 39 g of benzene is burnt in an open container                [MP PET 2000]

    A)                 122.25 kcal \[mo{{l}^{-1}}\]        

    B)                 390.5 kcal \[mo{{l}^{-1}}\]

    C)                 1562.0 kcal \[mo{{l}^{-1}}\]        

    D)                 586.75 kcal \[mo{{l}^{-1}}\]

    Correct Answer: B

    Solution :

           Heat evolved during burning of \[39g\]                                 \[{{C}_{6}}{{H}_{6}}=\frac{781.0\times 39}{78}=390.5\,kcal\,mo{{l}^{-1}}\]


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