JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Heat of reaction

  • question_answer
    Heat of formation of \[{{H}_{2}}O\] is \[-188\,kJ/mole\] and \[{{H}_{2}}{{O}_{2}}\] is \[-286\,kJ/mole.\] The enthalpy change for the reaction \[2{{H}_{2}}{{O}_{2}}\,\to \,2{{H}_{2}}O+{{O}_{2}}\] is   [BHU 2001]

    A)                 196 kJ   

    B)                 ? 196 kJ 

    C)                 984 kJ   

    D)                 ? 984 kJ

    Correct Answer: A

    Solution :

           \[{{H}_{2}}+\frac{1}{2}{{O}_{2}}\to {{H}_{2}}O\,\,\,\Delta H=-188\,kJ/mole\]     ..?..(i)            \[{{H}_{2}}+{{O}_{2}}\to {{H}_{2}}{{O}_{2}};\,\,\,\Delta H=-286\,kJ/mole\]                ..?.(ii)            By 2 × (i) and (ii)            \[2{{H}_{2}}+{{O}_{2}}\to 2{{H}_{2}}O\,;\,\,\Delta H=-376\,kJ/mole\]          ?..(iii)                     \[2{{H}_{2}}+2{{O}_{2}}\to 2{{H}_{2}}{{O}_{2}}\,\,\,\Delta H=-572\,kJ/mole\]          ?..(iv)            By (iii) ? (iv)                                 \[2{{H}_{2}}{{O}_{2}}\to 2{{H}_{2}}O+{{O}_{2}}\,\,\,\Delta H=+196\,kJ\].


You need to login to perform this action.
You will be redirected in 3 sec spinner