A) \[{{C}_{2}}{{H}_{2}}\]
B) \[{{C}_{2}}{{H}_{4}}\]
C) Both of these
D) None of these
Correct Answer: A
Solution :
\[\Delta H\]for \[{{C}_{2}}{{H}_{6}}=-341.1\,K\,cal\] its calorific value \[=\frac{-341.1}{30}=-11.37\,kcal/g\]. \[\Delta H\]for \[{{C}_{2}}{{H}_{2}}=-310.0\,kcal\] its Calorific value \[=\frac{-310.0\,}{26}=-11.92,\] hence \[{{C}_{2}}{{H}_{2}}\]is a better fuel.
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