A) 122.25 kcal \[mo{{l}^{-1}}\]
B) 390.5 kcal \[mo{{l}^{-1}}\]
C) 1562.0 kcal \[mo{{l}^{-1}}\]
D) 586.75 kcal \[mo{{l}^{-1}}\]
Correct Answer: B
Solution :
Heat evolved during burning of \[39g\] \[{{C}_{6}}{{H}_{6}}=\frac{781.0\times 39}{78}=390.5\,kcal\,mo{{l}^{-1}}\]You need to login to perform this action.
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