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JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Heat of reaction

  • question_answer
    When the aqueous solution of 0.5 mole \[HN{{O}_{3}}\] is mixed with the 0.3 mole of \[O{{H}^{-}}\] solution, then what will be the liberated heat (Enthalpy of neutralization is = 57.1 kJ) [Kerala CET 2005]

    A)                 28.5 kJ

    B)                 17.1 kJ

    C)                 45.7 kJ  

    D)                 1.7 kJ

    E)                 2.85 kJ

    Correct Answer: B

    Solution :

               0.3 mole \[O{{H}^{-}}\], neutralize 0.3 mole of \[HN{{O}_{3}}\]                                 Evolved heat, \[=57.1\times 0.3=17.13kJ\]


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