JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Heat of reaction

  • question_answer
    The enthalpies of combustion of carbon and carbon monodie are ?393.5 and ?283 kJ mol?1 respectivley. The enthalpy of formation of carbon monoxide per mole is [AIEEE 2004]

    A)                 \[-676.5\,kJ\]    

    B)                 \[676.5\,kJ\]

    C)                 \[110.5\,kJ\]      

    D)                 \[-110.5\,kJ\]

    Correct Answer: D

    Solution :

               \[C(s)+{{O}_{2}}(g)\to C{{O}_{2}}(g)\]                    \[\Delta H=-393.5\,KJ\,mo{{l}^{-1}}\]                                                  ?..(i)                    \[CO(g)+1/2{{O}_{2}}(g)\to C{{O}_{2}}(g)\]                    \[\Delta H=-283\,KJ\,mo{{l}^{-1}}\]                                                      ?..(ii)                    On substracting equation (ii) from equation (i)                    We get                    \[C(s)+{{O}_{2}}(g)\to CO(g)\]; \[\Delta H=-110.5\,KJ\,mo{{l}^{-1}}\]                                 The enthalpy of formation of carbon monooxide per mole \[=-110.5\,KJ\,mo{{l}^{-1}}\]


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