question_answer

\[\Delta H{{{}^\circ }_{f}}\] (298K) of methanol is given by the chemical equation             [AIIMS 2005]

A)                 \[C{{H}_{4}}(g)+1/2{{O}_{2}}(g)\to C{{H}_{3}}OH(g)\]

B)                 C (graphite) \[+1/2{{O}_{2}}(g)+2{{H}_{2}}(g)\to C{{H}_{3}}OH(l)\]

C)                 C (diamond) \[+1/2{{O}_{2}}(g)+2{{H}_{2}}(g)\to C{{H}_{3}}OH(l)\]

D)                 \[CO(g)+2{{H}_{2}}(g)\to C{{H}_{3}}OH(l)\]